Quick setup
Open the kRouter dashboard at http://localhost:20128
Go to Providers → click Atomesus
Paste your API key, click Save
Test the connection
Use in your IDE
Point any OpenAI-compatible client at kRouter using your local API key.
# Endpoint
http://localhost:20128/v1
# API key (from Dashboard → API Keys)
sk-krouter-XXXX
# Model
atms/<model-id>How Atomesus billing works with kRouter
Atomesus gives you free starting credits, then bills per token. kRouter tracks the remaining quota and fails over to another provider before you hit a wall. kRouter authenticates it via apikey. 1 model are routable as atms/<model>. Its catalog is fetched live, so new models appear without a kRouter update.
Through kRouter, Atomesus serves chat and code completion. Requests reach it through the same local OpenAI-compatible endpoint as every other provider, so switching to or from Atomesus is a one-line model change in your client rather than a rewrite.
OpenAI-compatible API access to Atomesus AI (cipher model). Requires Atomesus API key.
Atomesus models & pricing
These are the model ids kRouter routes to. This provider does not publish per-token rates.
| Model | Route as |
|---|---|
| Cipher | atms/cipher |
Atomesus links
Atomesus FAQ
Is Atomesus free through kRouter?
Atomesus is pay-per-token: you bring your own API key and are billed by Atomesus at their rates. kRouter adds nothing on top and is free and MIT-licensed.
How do I use Atomesus with Claude Code or Cursor?
Connect Atomesus in the kRouter dashboard, then point your tool at kRouter's local endpoint (http://localhost:20128/v1) with a kRouter API key. Any OpenAI-compatible client works, and models are addressed as atms/<model>.
Which Atomesus models can kRouter route to?
1 model, including Cipher. Every one is addressed as atms/<model> from any client.
What happens when Atomesus is rate limited?
kRouter detects the limit, parks that account until its real reset time, and fails over to your next connected account or provider — so the request still completes instead of erroring.